Eureka Math Grade 5 Module 4 Lesson 8 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 4 Lesson 8 Answer Key

Eureka Math Grade 5 Module 4 Lesson 8 Problem Set Answer Key

Question 1.
Laura and Sean find the product of \(\frac{2}{3}\) × 4 using different methods.
Laura: It’s 2 thirds of 4.
\(\frac{2}{3}\) × 4 = \(\frac{4}{3}\) + \(\frac{4}{3}\) = 2 × \(\frac{4}{3}\) = \(\frac{8}{3}\)

Sean: It’s 4 groups of 2 thirds.
\(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) = 4 × \(\frac{2}{3}\) = \(\frac{8}{3}\)
Use words, pictures, or numbers to compare their methods in the space below.
Answer:
Laura:
2/3 * 4 = 4/3 + 4/3 = 2*4/3 = 8/3
Sean:
2/3 + 2/3 + 2/3 + 2/3 = 4 * 2/3 = 8/3
Both methods are correct. 2/3 *4 is 2 thirds of 4, and it will also have the same product as the 4 groups of 2 thirds.

Question 2.
Rewrite the following addition expressions as fractions as shown in the example.
Example: \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) = (\(\frac{4 × 2}{3}\)) = \(\frac{8}{3}\)
a. \(\frac{7}{4}\) + \(\frac{7}{4}\) + \(\frac{7}{4}\) =
Answer:
21/4

Explanation:
The addition expression for the fraction given is :
7/4 + 7/4 + 7/4 = (3 × 7)/4 = 21/4

b. \(\frac{14}{5}\) + \(\frac{14}{5}\) =
Answer:
28/5

Explanation:
The addition expression for the fraction given is :
14/5 + 14/5 = (2×14)/5 = 28/5

c. \(\frac{4}{7}\) + \(\frac{4}{7}\) + \(\frac{4}{7}\) =
Answer:
12/7

Explanation:
4/7 +4/7 +4/7 = (3×4)/7 = 12/7

Question 3.
Solve and model each problem as a fraction of a set and as repeated addition.
Eureka Math Grade 5 Module 4 Lesson 8 Answer Key (1)
a. \(\frac{1}{2}\) × 8 8 × \(\frac{1}{2}\)
Answer:
1 ×8/2 = 1×4 = 4
8 × 1/2 = (8×1)/2
= 8/2
= 4

b. \(\frac{3}{5}\) × 10 10 × \(\frac{3}{5}\)
Answer:
6

Explanation:
3 ×10/5 = 3 × 2 = 6
10 × 3/5 = (10×3)/5 = 30/5 = 6

Question 4.
Solve each problem in two different ways as modeled in the example.
Eureka Math Grade 5 Module 4 Lesson 8 Answer Key (2)

a. 14 × \(\frac{3}{7}\) 14 × \(\frac{3}{7}\)
Answer:
6

Explanation:
(14×3)/7 = (7×2×3)/7 = (7×6)/7 = 6
(14 × 3)/7 = (2×3)/1 = 6

b. \(\frac{3}{4}\) × 36 \(\frac{3}{4}\) ×36
Answer:
27

Explanation:
(3×36)/4 = (3×4×9)/4 = (4×27)/4 = 27
(3×36)/4 = (3×9) = (3×9) = 27

c. 30 × \(\frac{13}{10}\) 30 × \(\frac{13}{10}\)
Answer:
39

Explanation:
(30×13)/10 = (10×3×13)/10 = (10×39)/10 = 39
(30 ×13)/10 = (3×13)/1 = 39

d. \(\frac{9}{8}\) ×32 \(\frac{9}{8}\) × 32
Answer:
36

Explanation:
(9×32)/8 = (9×4×8)/8 = (36×8)/8 = 36
(9×32)/8 = (9×32)/8 = (9×4)/1 = 36

Question 5.
Solve each problem any way you choose.
a. \(\frac{1}{2}\) × 60 \(\frac{1}{2}\) minute = __________ seconds
Answer:
30seconds

Explanation:
The answer and the procedure are explained clearly in the below steps.
1 minute = 60 seconds
(1×60)/2 = (1×30)/1 = 30

b. \(\frac{3}{4}\) × 60 \(\frac{3}{4}\) hour = __________ minutes
Answer:
45 minutes

Explanation:
The answer and the procedure are explained clearly in the below steps.
1 hour = 60 minutes
(3×60)/4 = (3×15)/1 = 45

c. \(\frac{3}{10}\) × 1,000 \(\frac{3}{10}\) kilogram = __________ grams”
Answer:
300 grams

Explanation:
The answer and the procedure are explained clearly in the below steps.
1 kilogram = 1000 grams
(3×1000)/1 = 300

d. \(\frac{4}{5}\) × 100 \(\frac{4}{5}\) meter = __________ centimeters
Answer:
80 centimeters

Explanation:
The answer and the procedure are explained clearly in the below steps.
1 meter
(4×100)/5 = (4×20)/1 = 80

Eureka Math Grade 5 Module 4 Lesson 8 Exit Ticket Answer Key

Solve each problem in two different ways as modeled in the example.
Eureka Math Grade 5 Module 4 Lesson 8 Answer Key (3)

a. \(\frac{2}{3}\) × 15 \(\frac{2}{3}\) × 15
Answer:
10

Explanation:
By solving the given question in two methods we could get the same answer i.e 10. The Explanation is given below.
2/3 × 15 = (2 ×15)/3 = 30/3 = 10
2/3 ×15 = (2×15)/3 = (2×5) = 10

b. \(\frac{5}{4}\) × 12 \(\frac{5}{4}\) × 12
Answer:
15

Explanation:
By solving the given question in two methods we could get the same answer i.e 15. The process for the question is done below.
5/4 × 12 = (5×12)/4 = (60)/4 =15
5/4 ×12 = ( 5×12)/4 = (5×3) =15

Eureka Math Grade 5 Module 4 Lesson 8 Homework Answer Key

Question 1.
Rewrite the following expressions as shown in the example.
Example: \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) + \(\frac{2}{3}\) = (\(\frac{4 × 2}{3}\)) = \(\frac{8}{3}\)

a. \(\frac{5}{3}\) + \(\frac{5}{3}\) + \(\frac{5}{3}\)
Answer:
5

Explanation:
(\(\frac{3 × 5}{3}\)) = \(\frac{15}{3}\) =5

b. \(\frac{13}{5}\) + \(\frac{13}{5}\)
Answer:
\(\frac{26}{5}\)

Explanation:
(\(\frac{2 × 13}{5}\)) = \(\frac{26}{5}\)

c. \(\frac{9}{4}\) + \(\frac{9}{4}\) + \(\frac{9}{4}\)
Answer:
\(\frac{27}{4}\)

Expalanation:
(\(\frac{3 × 9}{4}\)) = \(\frac{27}{4}\)

Question 2.
Solve each problem in two different ways as modeled in the example.
Eureka Math Grade 5 Module 4 Lesson 8 Answer Key (4)

a. \(\frac{3}{4}\) × 16 \(\frac{3}{4}\) × 16
Answer:
12

Explanation:
(\(\frac{3 × 16}{4}\)) = \(\frac{48}{4}\) = 12
(\(\frac{3 × 16}{4}\)) = \(\frac{3 × 4}{1}\) = 12

b. \(\frac{4}{3}\) × 12 \(\frac{4}{3}\) × 12
Answer:
16

Explanation:
(\(\frac{4 × 12}{3}\)) = \(\frac{48}{3}\) = 16
(\(\frac{4 × 12}{3}\)) = \(\frac{4 × 12}{1}\) = 16

c. 40 × \(\frac{11}{10}\) 40 × \(\frac{11}{10}\)
Answer:
44

Explanation:
(\(\frac{40 × 11}{10}\)) = \(\frac{440}{10}\) = 44
(\(\frac{40× 11}{10}\)) = \(\frac{4 × 11}{1}\) = \(\frac{44}{1}\) = 44

d. \(\frac{7}{6}\) × 36 \(\frac{7}{6}\)× 36
Answer:
42

Explanation:
(\(\frac{7 × 36}{6}\)) = \(\frac{252}{6}\) = 42
(\(\frac{7 × 36}{6}\)) = \(\frac{7 × 6}{1}\) = 42

e. 24 × \(\frac{5}{8}\) 24 × \(\frac{5}{8}\)
Answer:
15

Explanation:
(\(\frac{24 × 5}{8}\)) = \(\frac{126}{8}\) = 15
(\(\frac{24 × 5}{8}\)) = \(\frac{3 × 5}{1}\) = 15

f. 18 × \(\frac{5}{12}\) 18 × \(\frac{5}{12}\)
Answer:
7 1/2

Explanation:
(\(\frac{18 × 5}{12}\)) = \(\frac{90}{12}\) = 7 6/12 = 7 1/2
(\(\frac{18 × 5}{12}\)) = \(\frac{3 × 5 }{2}\) = \(\frac{15}{2}\)= 7 1/2

g. \(\frac{10}{9}\) × 21 \(\frac{10}{9}\) × 21
Answer:
23 3/9 = 23 1/3

Explanation:
(\(\frac{10 × 21}{9}\)) = \(\frac{210}{9}\) = 23 3/9 = 23 1/3
(\(\frac{10 × 21}{9}\)) = \(\frac{10 × 7}{3}\) = \(\frac{70}{3}\) = 23 1/3

Question 3.
Solve each problem any way you choose.

a. \(\frac{1}{3}\) × 60 \(\frac{1}{3}\) minute = _________ seconds
Answer:
20 seconds

Explanation:
(\(\frac{1 × 60}{3}\)) = \(\frac{60}{3\) = 20

b. \(\frac{4}{5}\) × 60 \(\frac{4}{5}\) hour = _________ minutes
Answer:
48 minutes

Explanation:
(\(\frac{4 × 60}{5}\)) = \(\frac{48}{1\) = 48

c. \(\frac{7}{10}\) × 1000 \(\frac{7}{10}\) kilogram = _________ grams
Answer:
700 grams

Explanation:
(\(\frac{7 × 1000}{10}\)) = \(\frac{700}{1\) = 700

d. \(\frac{3}{5}\)× 100 \(\frac{3}{5}\) meter = _________ centimeters
Answer:
60 centimeres

Explanation:
(\(\frac{3 × 100}{5}\)) = \(\frac{60}{1\) = 60

Eureka Math Grade 5 Module 4 Lesson 8 Answer Key (2024)

FAQs

What grade does Eureka math go up to? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What fraction of a yard does Regina buy 24 inches of trim for a craft project? ›

Regina buys 24 inches of trim for a craft project. a. What fraction of a yard does Regina buy? 24 in = 12 yd 36in = lyd s⇒→Lxfr = 24 x 36 xd Regina bays 12/25 yd.

What are the four core components of a Eureka Math TEKS lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket).

What type of math is Eureka math? ›

Eureka Math® is a math program designed to advance equity in the math classroom by helping students build enduring math knowledge. What's in the Program? Numbers should add up to more than the right answer.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What is the hardest math grade? ›

Generally speaking, the most rigorous math courses in high school include Advanced Placement (AP) Calculus AB and BC, AP Statistics, and for some, Multivariable Calculus (which might be offered at your school or at a local college).

What fraction of 1 yard is 3 in? ›

Expert-Verified Answer

For a question like this, the measures need to have the same units. It is convenient to use inches. A yard is 36 inches, so the fraction is ... 3 inches is 1/12 of a yard.

What percent of a yard is a foot in fraction form? ›

Answer and Explanation:

A foot is is 33.3333... % of a yard. A yard is three feet, which means that one foot is a third of a yard. The fraction 1/3rd in percentage terms is one divided by three, or .

Is Eureka Math scripted? ›

Eureka Math is scripted for the teacher and anticipates student responses, which is very useful for studying in advance. This makes each module easy to follow and easy to understand what is expected.

How many states use Eureka math? ›

We wrote EngageNY Math, and over time we developed that program into Eureka Math. The original OER curriculum is available on the EngageNY and Great Minds sites for free, and it has been downloaded over 13 million times by users in all 50 states, making Eureka Math the most widely used K–5 math program in the country.

How is Eureka Math organized? ›

The content in Eureka Math is organized around a story that merges its content. This story builds learners' understanding of concepts and improves their ability to manipulate units. Through Eureka Math, students learn commonalities between units and the unique features of the units.

Is Eureka Math good or bad? ›

Is Eureka Math a good curriculum? The answer to this question depends on the target audience. If you're a teacher in a public school who needs to cover State Standards and your goal is merely to prepare students for State tests, then Eureka may be a good curriculum for you.

Why are schools using Eureka Math? ›

Eureka Math, a Common Core-aligned curriculum published by the non-profit Great Minds Inc., equates mathematical concepts to stories, with the aim of developing conceptual understanding.

Who is the father of math Eureka? ›

Here's a closer look into this sudden discovery (the “Eureka!” moment): The famous Greek mathematician, physicist, and astronomer, Archimedes was born in 287 BC in Syracuse, a Greek colony in Sicily (an island now part of Italy).

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is 8th grade advanced math? ›

Eighth graders who score proficient or advanced are considered to have mastered concepts such as number sense and operations; expressions, equations, and inequalities; functions; geometry and measurement; and data, analysis, and statistics.

What grade level does prodigy math go up to? ›

With 1,500+ curriculum-aligned math skills for 1st to 8th grade, Prodigy Math is so much more than a game. Prodigy Math is an engaging game-based learning platform that's dedicated to improving students' confidence and achievements in math.

What is the highest math class ever? ›

Math 55 is a two-semester freshman undergraduate mathematics course at Harvard University founded by Lynn Loomis and Shlomo Sternberg. The official titles of the course are Studies in Algebra and Group Theory (Math 55a) and Studies in Real and Complex Analysis (Math 55b).

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